问题 解答题
求多项式-
1
2
x2+4xy-
3
2
y2
-2x2+xy-
1
2
y2
的差.
答案

-

1
2
x2+4xy-
3
2
y2)-(-2x2+xy-
1
2
y2

=-

1
2
x2+4xy-
3
2
y2+2x2-xy+
1
2
y2

=(-

1
2
+2)x2+(4-1)xy+(-
3
2
+
1
2
)y2

=

3
2
x2+3xy-y2

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