问题
解答题
求多项式-
|
答案
(-
x2+4xy-1 2
y2)-(-2x2+xy-3 2
y2)1 2
=-
x2+4xy-1 2
y2+2x2-xy+3 2
y21 2
=(-
+2)x2+(4-1)xy+(-1 2
+3 2
)y21 2
=
x2+3xy-y2.3 2
求多项式-
|
(-
x2+4xy-1 2
y2)-(-2x2+xy-3 2
y2)1 2
=-
x2+4xy-1 2
y2+2x2-xy+3 2
y21 2
=(-
+2)x2+(4-1)xy+(-1 2
+3 2
)y21 2
=
x2+3xy-y2.3 2