问题
解答题
(1)计算:(1-
(2)先化简,再求值:5a2+3b2+2(a2-b2)-(5a2-3b2),其中a=-1,b=
|
答案
(1)原式=
×(-6)+4×(-3)=-2+(-12)=-14;1 3
(2)原式=5a2+3b2+2a2-2b2-5a2+3b2=2a2+4b2,
当a=-1,b=
时,1 2
原式=2×(-1)2+4×(
)2=3.1 2
(1)计算:(1-
(2)先化简,再求值:5a2+3b2+2(a2-b2)-(5a2-3b2),其中a=-1,b=
|
(1)原式=
×(-6)+4×(-3)=-2+(-12)=-14;1 3
(2)原式=5a2+3b2+2a2-2b2-5a2+3b2=2a2+4b2,
当a=-1,b=
时,1 2
原式=2×(-1)2+4×(
)2=3.1 2