问题 解答题
先化简,再求值
(1)3x2y-[2xy2-2(xy-
3
2
x2y)+xy]+3xy2
,其中x=3,y=-
1
3

(2)已知a+b=-2,ab=3,求2[ab+(-3a)]-3(2b-ab)的值.
答案

(1)原式=3x2y-[2xy2-2xy+3x2y+xy]+3xy2

=3x2y-2xy2+2xy-3x2y-xy+3xy2

=xy+xy2

把x=3,y=-

1
3
代入得:原式=-1+
1
3
=-
2
3

(2)∵a+b=-2,ab=3,

∴原式=2[ab-3a]-6b+3ab

=2ab-6a-6b+3ab

=5ab-6(a+b)

=5×3-6×(-2)

=27.

综合
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