问题
解答题
先化简,再求值 (1)3x2y-[2xy2-2(xy-
(2)已知a+b=-2,ab=3,求2[ab+(-3a)]-3(2b-ab)的值. |
答案
(1)原式=3x2y-[2xy2-2xy+3x2y+xy]+3xy2
=3x2y-2xy2+2xy-3x2y-xy+3xy2
=xy+xy2,
把x=3,y=-
代入得:原式=-1+1 3
=-1 3
.2 3
(2)∵a+b=-2,ab=3,
∴原式=2[ab-3a]-6b+3ab
=2ab-6a-6b+3ab
=5ab-6(a+b)
=5×3-6×(-2)
=27.