问题 解答题
先化简再求值.
3x2y-[2xy2-2(xy-
3
2
x2y)+xy]+3xy2,其中x=3,y=-
1
3

②(2a+3b-2ab)-(a+4b+ab)-(3ab-2a+2b),其中a-b=5,ab=-5
答案

①原式=3x2y-(2xy2-2xy+3x2y+xy)+3xy2

=3x2y-2xy2+2xy-3x2y-xy+3xy2

=xy2+xy

将x=3,y=-

1
3
代入上式,得

上式=3×(-

1
3
)2+3×(-
1
3
)

=3×

1
9
-1

=

1
3
-1

=-

2
3

②(2a+3b-2ab)-(a+4b+ab)-(3ab-2a+2b)

=2a+3b-2ab-a-4b-ab-3ab+2a-2b

=3a-3b-6ab

=3(a-b)-6ab

将a-b=5,ab=-5代入上式,得

上式=3×5-6×(-5)

=15+30

=45.

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