问题
解答题
求值:5a2-[a2-(2a-5a2)-2(a2-3a)],其中a=-2.
答案
原式=5a2-[a2-2a+5a2-2a2+6a]
=5a2-[4a2+4a]
=5a2-4a2-4a
=a2-4a
当a=-2时,原式=12.
求值:5a2-[a2-(2a-5a2)-2(a2-3a)],其中a=-2.
原式=5a2-[a2-2a+5a2-2a2+6a]
=5a2-[4a2+4a]
=5a2-4a2-4a
=a2-4a
当a=-2时,原式=12.