问题
解答题
（1）计算：
（2）解分式方程：
|
答案
（1）原式=
| 4a |
| (a+1)(a-1) |
| a+1 |
| a-1 |
=
| 4a-(a+1)2 |
| (a+1)(a-1) |
=-
| a2-2a+1 |
| (a+1)(a-1) |
=-
| (a-1)2 |
| (a+1)(a-1) |
=-
| a-1 |
| a+1 |
（2）去分母得3（x-1）+6x=7，
解得x=
| 10 |
| 9 |
经检验：x=
| 10 |
| 9 |
∴x=
| 10 |
| 9 |
搜题请搜索小程序“爱下问搜题”
（1）计算：
（2）解分式方程：
|
（1）原式=
| 4a |
| (a+1)(a-1) |
| a+1 |
| a-1 |
=
| 4a-(a+1)2 |
| (a+1)(a-1) |
=-
| a2-2a+1 |
| (a+1)(a-1) |
=-
| (a-1)2 |
| (a+1)(a-1) |
=-
| a-1 |
| a+1 |
（2）去分母得3（x-1）+6x=7，
解得x=
| 10 |
| 9 |
经检验：x=
| 10 |
| 9 |
∴x=
| 10 |
| 9 |