问题 解答题
先化简,再求值:3a2b-{2a2b+[9a2b-2(6a2b+4a2)]-(3a2b-8a2)},其中a=-
1
2
,b=-2.
答案

3a2b-{2a2b+[9a2b-2(6a2b+4a2)]-(3a2b-8a2)}

=3a2b-{2a2b+[9a2b-12a2b-8a2]-3a2b+8a2},

=3a2b-{2a2b+9a2b-12a2b-8a2-3a2b+8a2},

=3a2b-2a2b-9a2b+12a2b+8a2+3a2b-8a2

=7a2b

当a=-

1
2
,b=-2时,

原式=7×(-

1
2
2×(-2)=
7
2

解答题
单项选择题 A1型题