问题 解答题
递等式计算:
(160-48÷12)×4336÷[(36-29)×6]62×(300-145÷5)
答案

(1)(160-48÷12)×4,

=(160-4)×4,

=156×4,

=624;

(2)336÷[(36-29)×6],

=336÷[7×6],

=336÷42,

=8;

(3)62×(300-145÷5),

=62×(300-29),

=62×271,

=16802.

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