问题
解答题
(1)解方程:
(2)先化简再求值:(5x2y-2xy2-3xy)-(2xy+5x2y+2xy2),其中x=-
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答案
(1)两边同乘以0.1得:0.5(x-1)-0.2(x+1)=0.2,
去括号得:0.5x-0.5-0.2x-0.2=0.2,
移项得:0.5x-0.2x=0.2+0.5+0.2,
合并同类项:0.3x=0.9,
系数化为l,得x=3;
(2)原式=5x2y-2xy2-3xy-2xy-5x2y
=-xy(4y+5),
把x=-
,y=-1 3
代入得:原式=-(-1 4
)×(-1 3
)×(-1+4)=-1 4
.1 3