问题
解答题
先化简,再求值: (1)2(x-y)-3(
(2)-3(x2-xy)+2(x2+xy-1)+1 其中x=
|
答案
(1)2(x-y)-3(
x-2y-1)1 3
=2x-2y-x+6y+3
=(2-1)x+(-2+6)y+3
=x+4y+3,
当x=2001,y=-
时,原式=2011+4×(-1 4
)+3=2011-1+3=2003;1 4
(2)-3(x2-xy)+2(x2+xy-1)+1
=-3x2+3xy+2x2+2xy-2+1
=(-3+2)x2+(3+2)xy+(-2+1)
=-x2+5xy-1,
当x=
,y=-2时,原式=-(1 2
)2+5×1 2
×(-2)-1=-1 2
-5-1=-1 4
.25 4