问题
解答题
(1)化简5(a2b-2ab2+c)-4(2c+3a2b-ab2) (2)先化简,再求值:
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答案
(1)原式=5a2b-10ab2+c-8c+3a2b+4ab2
=8a2b-6ab2-8c;
(2)原式=
a-2a+1 2
b2-2 3
a+2b23 2
=-a+
b2,8 3
当a=-2,b=
时,原式=2+3 2
×8 3
=8.9 4
(1)化简5(a2b-2ab2+c)-4(2c+3a2b-ab2) (2)先化简,再求值:
|
(1)原式=5a2b-10ab2+c-8c+3a2b+4ab2
=8a2b-6ab2-8c;
(2)原式=
a-2a+1 2
b2-2 3
a+2b23 2
=-a+
b2,8 3
当a=-2,b=
时,原式=2+3 2
×8 3
=8.9 4