问题 解答题
化简
(1)
1
2
a2b-5ac-(3a2c-a2b)+(3ac-4a2c)

(2)3x2-[7x-(4x-3)-2x2]
(3)-5a+(3a-2)-
1
3
(3a-7)

(4)(5a2+2a-1)-4(3-8a+2a2
答案

(1)原式=

1
2
a2b-5ac-3a2c+a2b+3ac-4a2c

=

3
2
a2b-2ac-7a2c

(2)原式=3x2-[7x-4x+3-2x2]

=3x2-7x+4x-3+2x2]

=5x2-3x-3

(3)原式=-5a+3a-2-a+

7
3

=-3a+

1
3

(4)原式=5a2+2a-1-12+32a-8a2

=-3a2+34a-13

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