问题
解答题
先化简,再求值-32y-4(xy2-
|
答案
原式=-3x2y-4xy2+6x2y-5xy2+2x2y
=5x2y-9xy2,
当x=-
,y=4时,原式=5×(-1 2
)2×4-9×(-1 2
)×42=5+72=77.1 2
先化简,再求值-32y-4(xy2-
|
原式=-3x2y-4xy2+6x2y-5xy2+2x2y
=5x2y-9xy2,
当x=-
,y=4时,原式=5×(-1 2
)2×4-9×(-1 2
)×42=5+72=77.1 2