问题
解答题
先化简,再求值:(1)2(2a2-2a-5)-(4a2-3a-6),其中a=-3; (2)-x2+[3xy2-
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答案
(1)2(2a2-2a-5)-(4a2-3a-6)
=4a2-4a-10-4a2+3a+6
=-a-4,
当a=-3时-a-4=-(-3)-4=-1;
(2)-x2+[3xy2-
(4x2-8xy2)+x2]-7xy21 2
=-x2+[3xy2-2x2-4xy2)+x2]-7xy2
=-x2+[7xy2-x2]-7xy2
=-x2+7xy2-x2-7xy2=-2x2
当x=-
,y=-2011时,3 2
-2x2=-2×(-
)2=-3 2
.9 2