问题 解答题
先化简,再求值:(1)2(2a2-2a-5)-(4a2-3a-6),其中a=-3;
(2)-x2+[3xy2-
1
2
(4x2-8xy2)+x2]-7xy2,其中x=-
3
2
,y=-2011.
答案

(1)2(2a2-2a-5)-(4a2-3a-6)

=4a2-4a-10-4a2+3a+6  

=-a-4,

当a=-3时-a-4=-(-3)-4=-1;   

(2)-x2+[3xy2-

1
2
(4x2-8xy2)+x2]-7xy2

=-x2+[3xy2-2x2-4xy2)+x2]-7xy2  

=-x2+[7xy2-x2]-7xy2      

=-x2+7xy2-x2-7xy2=-2x2

当x=-

3
2
,y=-2011时,

-2x2=-2×(-

3
2
2=-
9
2

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