问题
解答题
4x2y-[6xy-2(3xy-2)-x2y]+1,其中x=-
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答案
4x2y-[6xy-2(3xy-2)-x2y]+1
=4x2y-[6xy-(6xy-4)-x2y]+1
=4x2y-(6xy-6xy+4-x2y)+1
=4x2y-(4-x2y)+1
=4x2y-4+x2y+1
=5x2y-3,
当x=-
,y=4时,原式=5x2y-3=5×(-1 2
)2×4-3=5-3=2.1 2
4x2y-[6xy-2(3xy-2)-x2y]+1,其中x=-
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4x2y-[6xy-2(3xy-2)-x2y]+1
=4x2y-[6xy-(6xy-4)-x2y]+1
=4x2y-(6xy-6xy+4-x2y)+1
=4x2y-(4-x2y)+1
=4x2y-4+x2y+1
=5x2y-3,
当x=-
,y=4时,原式=5x2y-3=5×(-1 2
)2×4-3=5-3=2.1 2