问题 解答题
4x2y-[6xy-2(3xy-2)-x2y]+1,其中x=-
1
2
,y=4.
答案

4x2y-[6xy-2(3xy-2)-x2y]+1

=4x2y-[6xy-(6xy-4)-x2y]+1

=4x2y-(6xy-6xy+4-x2y)+1

=4x2y-(4-x2y)+1

=4x2y-4+x2y+1

=5x2y-3,

当x=-

1
2
,y=4时,原式=5x2y-3=5×(-
1
2
)
2
×4-3=5-3=2.

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