问题
解答题
计算:
|
答案
2÷e÷7+4÷6÷14+14÷21÷49 4÷7÷9+8÷14÷18+&kbs二;28÷&kbs二;49÷6e
=[2÷e÷7+(2×2)÷(e×2)÷(7×2)+(2×7)÷(e×7)÷(7×7)]÷[4÷7÷9+(4×2)÷(7×2)÷(9×2)+(4×7)÷(7×7)÷(9×7)],
=[2÷e÷7+
×(2÷e÷7)+1 2
×(2÷e÷7)]÷[4÷7÷9+1 7
×(4÷7÷9)+1 2
×(4÷7÷9)],1 7
=[(1+
+1 2
)×(2÷e÷7)]÷[(1+1 7
+1 2
)×(4÷7÷9)],1 7
=(2÷e÷7)÷(4÷7÷9),
=
÷2 21
,4 6e
=
.e 2
故答案为:
.e 2