问题 解答题
化简
(1)3a2-2a+4a2-7a;                
(2)8a-a3+a2+4a3-a2-7a-6;
(3)2(2a-3b)+3(2b-3a);       
(4)(-2ab+3a)-(2a-b)+6ab;
(5)a2-[-4ab+(ab-a2)]-2ab;     
(6)
1
2
a2-[
1
2
(ab-a2)+4ab]-
1
2
ab.
答案

(1)原式=3a2+4a2-2a-7a=7a2-9a;

(2)原式=-a3+4a3+a2-a2+8a-7a-6

=3a3+a-6;

(3)原式=4a-6b+6b-9a=-5a;

(4)原式=-2ab+3a-2a+b+6ab

=4ab+a+b;

(5)原式=a2-[-4ab+ab-a2]-2ab

=a2-4ab-ab+a2-2ab

=2a2+ab;

(6)原式=

1
2
a2-[
1
2
ab-
1
2
a2+4ab]-
1
2
ab

=

1
2
a2-
1
2
ab+
1
2
a2-4ab-
1
2
ab

=a2-5ab.

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