试用向量证明三垂线定理及其逆定理.
证明:设直线a上非零向量
,要证a⊥PA?a⊥OA,a
即证
?a
=0?AP
?a
=0.AO
∵a?α,
?a
=0,OP
∴
?a
=AP
?(a
+AO
)=OP
?a
+AO
?a
=OP
?a
.AO
∴
?a
=0?AP
?a
=0,即a⊥PA?a⊥OA.AO
试用向量证明三垂线定理及其逆定理.
证明:设直线a上非零向量
,要证a⊥PA?a⊥OA,a
即证
?a
=0?AP
?a
=0.AO
∵a?α,
?a
=0,OP
∴
?a
=AP
?(a
+AO
)=OP
?a
+AO
?a
=OP
?a
.AO
∴
?a
=0?AP
?a
=0,即a⊥PA?a⊥OA.AO