问题 解答题
已知
ab
a+b
=4,
ac
a+c
=5,
bc
b+c
=6.
求17a+13b-7c的值.
答案

ab
a+b
=4⇒
a+b
ab
=
1
4
1
a
+
1
b
=
1
4
①,

同理得:

1
a
+
1
c
=
1
5
②,
1
b
+
1
c
=
1
6
③,

将①②③式相加得:

1
a
+
1
b
+
1
c
=
37
120
④.

④-①得

1
c
=
7
120
⇒c=
120
7

④-②得

1
b
=
13
120
⇒b=
120
13

④-③得

1
a
=
17
120
⇒a=
120
17

∴17a+13b-7c=120+120-120=120.

故17a+13b-7c的值为120.

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