问题
解答题
计算
|
答案
原式=(
-1 2
)+(1 3
-1 3
)+(1 4
-1 4
)+…+(1 5
-1 n
)1 n+1
=
-1 2
+1 3
-1 3
+1 4
-1 4
+…+1 5
-1 n 1 n+1
=
-1 2 1 n+1
=
.n-1 2n+2
计算
|
原式=(
-1 2
)+(1 3
-1 3
)+(1 4
-1 4
)+…+(1 5
-1 n
)1 n+1
=
-1 2
+1 3
-1 3
+1 4
-1 4
+…+1 5
-1 n 1 n+1
=
-1 2 1 n+1
=
.n-1 2n+2