问题
解答题
计算或化简 (1)计算:
(2)先化简,再求值:(
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答案
(1)原式=x2-y2 y-x
=(x+y)(x-y) y-x
=-(x+y);
(2)原式=
•3x(x+1)-x(x-1) (x+1)(x-1) (x+1)(x-1) x
=
•x(x2+4) (x+1)(x-1) (x+1)(x-1) x
=2x+4,
当x=2时,原式=4+4=8.
计算或化简 (1)计算:
(2)先化简,再求值:(
|
(1)原式=x2-y2 y-x
=(x+y)(x-y) y-x
=-(x+y);
(2)原式=
•3x(x+1)-x(x-1) (x+1)(x-1) (x+1)(x-1) x
=
•x(x2+4) (x+1)(x-1) (x+1)(x-1) x
=2x+4,
当x=2时,原式=4+4=8.