问题 解答题
计算:
(1)
x2
x-1
-x-1
(2)
x+2
x2-2x
-
x-1
x2-4x+4
(3)(xy-x2)(
1
x
+
1
y-x
)
(4)(x-1-
8
x+1
)÷
x+3
x+1
答案

(1)

x2
x-1
-x-1=
x2
x-1
-(x+1)
=
x2
x-1
-
(x-1)(x+1)
x-1
=
x2-x2+1
x-1
=
1
x-1

(2)

x+2
x2-2x
-
x-1
x2-4x+4
=
x+2
x(x-2)
-
x-1
(x-2)2
=
(x+2)(x-2)
x(x-2)2
-
x(x-1)
x(x-2)2
=
x-4
x(x-2)2

(3)(xy-x2)(

1
x
+
1
y-x
)=x(y-x)•
y-x+x
x(y-x)
=y,

(4)(x-1-

8
x+1
)÷
x+3
x+1
=
x2-1-8
x+1
x+1
x+3
=
(x+3)(x-3)
x+1
x+1
x+3
=x-3.

单项选择题
单项选择题