问题
解答题
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答案
(1)
-x-1=x2 x-1
-(x+1)=x2 x-1
-x2 x-1
=(x-1)(x+1) x-1
=x2-x2+1 x-1
,1 x-1
(2)
-x+2 x2-2x
=x-1 x2-4x+4
-x+2 x(x-2)
=x-1 (x-2)2
-(x+2)(x-2) x(x-2)2
=x(x-1) x(x-2)2
,x-4 x(x-2)2
(3)(xy-x2)(
+1 x
)=x(y-x)•1 y-x
=y,y-x+x x(y-x)
(4)(x-1-
)÷8 x+1
=x+3 x+1
•x2-1-8 x+1
=x+1 x+3 (x+3)(x-3) x+1
=x-3.x+1 x+3