问题
解答题
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答案
原式=
-2y+x x2-y2
-y x2-y2
=2x x2-y2
=2y+x-y-2x x2-y2
=-y-x (x+y)(x-y)
．1 x+y
搜题请搜索小程序“爱下问搜题”
|
原式=
-2y+x x2-y2
-y x2-y2
=2x x2-y2
=2y+x-y-2x x2-y2
=-y-x (x+y)(x-y)
．1 x+y