问题
填空题
观察下列各式:
|
答案
原式=
(1-1 2
+1 3
-1 3
+1 5
-1 5
+…+1 7
-1 2n-1
)1 2n+1
=
(1-1 2
)1 2n+1
=
.n 2n+1
观察下列各式:
|
原式=
(1-1 2
+1 3
-1 3
+1 5
-1 5
+…+1 7
-1 2n-1
)1 2n+1
=
(1-1 2
)1 2n+1
=
.n 2n+1