问题
解答题
化简计算(式中a,b,c两两不相等):
|
答案
原式=
+(a-b)+(a-c) (a-b)(a-c)
+(b-c)+(b-a) (b-c)(b-a) (c-a)+(c-b) (c-a)(c-b)
=
+1 a-c
+1 a-b
+1 b-a
+1 b-c
+1 c-b
=0.1 c-a
化简计算(式中a,b,c两两不相等):
|
原式=
+(a-b)+(a-c) (a-b)(a-c)
+(b-c)+(b-a) (b-c)(b-a) (c-a)+(c-b) (c-a)(c-b)
=
+1 a-c
+1 a-b
+1 b-a
+1 b-c
+1 c-b
=0.1 c-a