问题 解答题
计算与化简
(1)
5
8
×(-4)2-0.25×(-5)÷(-
1
2
3
(2)当x=-
1
2
,y=-3时,求代数式3(x2-2xy)-[3x2-2y+2(xy+y)]的值.
答案

(1)

5
8
×(-4)2-0.25×(-5)÷(-
1
2
3

=

5
8
×16-0.25×(-5)÷(-
1
8

=10-0.25×5×8

=10-10

=0;

(2)3(x2-2xy)-[3x2-2y+2(xy+y)]

=3x2-6xy-[3x2-2y+2xy+2y]

=3x2-6xy-3x2-2xy

=-8xy;

当x=-

1
2
,y=-3时,

-8xy=-8×(-

1
2
)×(-3)=-12.

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