问题
解答题
先化简,再求值. (1)2(x2y+xy)-3(x2y-xy)-4x2y,其中x=1,y=-1. (2)(xy-
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答案
(1)原式=2x2y+2xy-3x2y+3xy-4x2y
=-5x2y+5xy,
当x=1,y=-1时,原式=5-5=0;
(2)原式=xy-
y-3 2
-xy+1 2
x-13 2
=
x-3 2
y-3 2
,3 2
当x=
,y=10 3
时,原式=5-4-8 3
=-3 2
.1 2