问题
解答题
先化简,再求值:4xy-[(x2+5xy-y2)-(x2+3xy-2y2)],其中x=-
|
答案
原式=4xy-(x2+5xy-y2)+(x2+3xy-2y2)
=4xy-x2-5xy+y2+x2+3xy-2y2
=2xy-y2,
当x=-
,y=-1 4
时,原式=2×(-1 2
)×(-1 4
)-(-1 2
)2=0.1 2
先化简,再求值:4xy-[(x2+5xy-y2)-(x2+3xy-2y2)],其中x=-
|
原式=4xy-(x2+5xy-y2)+(x2+3xy-2y2)
=4xy-x2-5xy+y2+x2+3xy-2y2
=2xy-y2,
当x=-
,y=-1 4
时,原式=2×(-1 2
)×(-1 4
)-(-1 2
)2=0.1 2