问题 解答题
(1)计算:-25÷(-4)×(
1
2
)2-12×(-15+24)3

(2)先化简,再求值:3x2y-[2x2y-3(2xy-x2y)-xy],其中x=-1,y=-2.
答案

(1)原式=-32÷(-4)×

1
4
-12×1=2-12=-10;

(2)原式=3x2y-[2x2y-6xy+3x2y-xy]=3x2y-(5x2y-7xy)=3x2y-5x2y+7xy=-2x2y+7xy,

当x=-1,y=-2时,原式=-2x2y+7xy=18.

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