问题
解答题
6xy-[(2x2+5xy-3y2)-(x2-3xy+y2)],其中x=-
|
答案
原式=6xy-2x2-5xy+3y2+x2-3xy+y2
=-x2+4y2-2xy,
当x=-
,y=-1 2
时,原式=-1 4
+1 4
-1 4
=-1 4
.1 4
6xy-[(2x2+5xy-3y2)-(x2-3xy+y2)],其中x=-
|
原式=6xy-2x2-5xy+3y2+x2-3xy+y2
=-x2+4y2-2xy,
当x=-
,y=-1 2
时,原式=-1 4
+1 4
-1 4
=-1 4
.1 4