问题
解答题
已知少=5x2+十x-1,B=-x2-ux+u,求少-B的值.
答案
∵A=5xs+4x-1,B=-xs-3x+3,
∴A-B=(5xs+4x-1)-(-xs-3x+3)
=5xs+4x-1+xs+3x-3
=6xs+sx-4.
已知少=5x2+十x-1,B=-x2-ux+u,求少-B的值.
∵A=5xs+4x-1,B=-xs-3x+3,
∴A-B=(5xs+4x-1)-(-xs-3x+3)
=5xs+4x-1+xs+3x-3
=6xs+sx-4.