问题
解答题
(1)计算:
(2)若a-1<0,比较
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答案
(1)原式=
-a(a-2) (a-1)(a-2) (a-1)2 (a-1)(a-2)
=a(a-2)-(a-1)2 (a-1)(a-2)
=a2-2a-a2+2a-1 (a-1)(a-2)
=-
;1 (a-1)(a-2)
(2)根据(1)得:
-a a-1
=-a-1 a-2
,1 (a-1)(a-2)
当a-1<0时,a-2<0,则(a-1)(a-2)>0,
∴-
<0,1 (a-1)(a-2)
∴
<a a-1
.a-1 a-2