问题
选择题
复数z=
|
答案
z=
=a+i 3+4i (a+i)(3-4i) (3+4i)(3-4i)
=3a+3i-4ai-4i2 25
=3a+4+(3-4a)i 25
=
+3a+4 25
i,3-4a 25
∵复数z=
∈R,a+i 3+4i
∴
=0,3-4a 25
∴a=
.3 4
故选B.
复数z=
|
z=
=a+i 3+4i (a+i)(3-4i) (3+4i)(3-4i)
=3a+3i-4ai-4i2 25
=3a+4+(3-4a)i 25
=
+3a+4 25
i,3-4a 25
∵复数z=
∈R,a+i 3+4i
∴
=0,3-4a 25
∴a=
.3 4
故选B.