问题
解答题
计算下列各题: (1)
|
答案
(1)原式=
•2a a+b (a+b)(a-b) 2ab
=
,a-b b
(2)原式=
-2x (x+2y)(x-2y) x+2y (x+2y)(x-2y)
=2x-x-2y (x+2y)(x-2y)
=x-2y (x+2y)(x-2y)
=
.1 x+2y
计算下列各题: (1)
|
(1)原式=
•2a a+b (a+b)(a-b) 2ab
=
,a-b b
(2)原式=
-2x (x+2y)(x-2y) x+2y (x+2y)(x-2y)
=2x-x-2y (x+2y)(x-2y)
=x-2y (x+2y)(x-2y)
=
.1 x+2y