问题
解答题
计算：
|
答案
-2 a2+2a+1 2 a+1
=
-2 (a+1)2 2 a+1
=
-2 (a+1)2 2(a+1) (a+1)2
=2-2(a+1) (a+1)2
=2-2a-2 (a+1)2
=-
．2a a2+2a+1
搜题请搜索小程序“爱下问搜题”
计算：
|
-2 a2+2a+1 2 a+1
=
-2 (a+1)2 2 a+1
=
-2 (a+1)2 2(a+1) (a+1)2
=2-2(a+1) (a+1)2
=2-2a-2 (a+1)2
=-
．2a a2+2a+1
(n为自然数)，试确定常数α，β的值，使
都存在．