问题 解答题
计算:
(1)
4
x2-4
+
2
x+2
-
1
x-2

(2)(
a2
b
)2•(-b2a-2)3÷(-
b
a
)4
答案

(1)原式=

4
(x+2)(x-2)
+
2(x-2)
(x+2)(x-2)
-
x+2
(x+2)(x-2)

=

4+2(x-2)-(x+2)
(x+2)(x-2)

=

x-2
(x+2)(x-2)

=

1
x+2

(2)原式=

a4
b2
•(-
b6
a6
)×
a4
b4

=-a2

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