问题
解答题
计算: (1)
(2)(
|
答案
(1)原式=
+4 (x+2)(x-2)
-2(x-2) (x+2)(x-2) x+2 (x+2)(x-2)
=4+2(x-2)-(x+2) (x+2)(x-2)
=x-2 (x+2)(x-2)
=
;1 x+2
(2)原式=
•(-a4 b2
)×b6 a6 a4 b4
=-a2.
计算: (1)
(2)(
|
(1)原式=
+4 (x+2)(x-2)
-2(x-2) (x+2)(x-2) x+2 (x+2)(x-2)
=4+2(x-2)-(x+2) (x+2)(x-2)
=x-2 (x+2)(x-2)
=
;1 x+2
(2)原式=
•(-a4 b2
)×b6 a6 a4 b4
=-a2.