问题 解答题
计算:
(1)16÷(-2)3-(
1
3
-1+(
3
-1)0         (2)
a+1
a-1
-
a2+a
a2-1
答案

(1)原式=16÷(-8)-3+1

=-2-3+1

=-4;

(2)原式=

a+1
a-1
-
a(a+1)
(a+1)(a-1)

=

a+1
a-1
-
a
a-1

=

1
a-1

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