问题
填空题
计算:
|
答案
原式=
-y (y+x)(y-x) 1 y+x
=
-y (y+x)(y-x) y-x (y+x)(y-x)
=y-(y-x) (y+x)(y-x)
=x (y+x)(y-x)
=
.x y2-x2
故答案为:
.x y2-x2
计算:
|
原式=
-y (y+x)(y-x) 1 y+x
=
-y (y+x)(y-x) y-x (y+x)(y-x)
=y-(y-x) (y+x)(y-x)
=x (y+x)(y-x)
=
.x y2-x2
故答案为:
.x y2-x2