问题
解答题
计算: (1)3-1-(
(2)(-2m2n-2)2•(2m-1n3)-2; (3)
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答案
(1)原式=
-1+1 3
+4=1-1+4=4;2 3
(2)原式=4m4n-4×
m2n-6=m6n-10=1 4
;m6 n10
(3)原式=
+2(a-2) (a+3)2
=(a-2)(a+3) (a+3)2
=2(a-2)+(a-2)(a+3) (a+3)2
.(a-2)(a+5) (a+3)3