问题 解答题
计算:
(1)3-1-(
5
-2)0+
4
9
+(-2)2

(2)(-2m2n-22•(2m-1n3-2
(3)
2a-4
a2+6a+9
+
a-2
a+3
答案

(1)原式=

1
3
-1+
2
3
+4=1-1+4=4;

(2)原式=4m4n-4×

1
4
m2n-6=m6n-10=
m6
n10

(3)原式=

2(a-2)
(a+3)2
+
(a-2)(a+3)
(a+3)2
=
2(a-2)+(a-2)(a+3)
(a+3)2
=
(a-2)(a+5)
(a+3)3

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