问题
解答题
计算
|
答案
设2x2+3x=y，则
原式=
-1 y-1
+2 y+1 1 y+3
=(y+1)(y+3)-2(y-1)(y+3)+(y-1)(y+1) (y-1)(y+1)(y+3)
=8 (y-1)(y+1)(y+3)
=
．8 (2x2+3x-1)(2x2+3x+1)(2x2+3x+3)
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计算
|
设2x2+3x=y，则
原式=
-1 y-1
+2 y+1 1 y+3
=(y+1)(y+3)-2(y-1)(y+3)+(y-1)(y+1) (y-1)(y+1)(y+3)
=8 (y-1)(y+1)(y+3)
=
．8 (2x2+3x-1)(2x2+3x+1)(2x2+3x+3)