问题 解答题
计算化简:
x
x2+3x+2
+
x
x2+x-2
+
2
1-x2
答案

原式=

x
(x+2)(x+1)
+
x
(x+2)(x-1)
+
2
(1+x)(1-x)

=

x(x-1)
(x+2)(x+1)(x-1)
+
x(x+1)
(x+2)(x+1)(x-1)
-
2(x+2)
(x+2)(x+1)(x-1)

=

x2-x +x2+x-2x-4
(x+2)(x2-1)

=

2x2-2x-4
(x+2)(x+1)(x-1)

=

2(x-2)(x+1)
(x+2)(x+1)(x-1)

=

2x-4
x2+x-2

问答题 简答题
多项选择题