问题
解答题
计算: (1)
(2)-3xy2÷
(3)
(4)
|
答案
(1)原式=-3ab2 24a2b
=-
;b 8a
(2)原式=-3xy2•5x 6y2
=-
;5x2 2
(3)原式=
•x(x-1) (x+1) (x+1)(x-1) (x-1)2
=x;
(4)原式=
•a(a+3b) -(a+b)(a-b) a-b a+3b
=-
.a a+b
计算: (1)
(2)-3xy2÷
(3)
(4)
|
(1)原式=-3ab2 24a2b
=-
;b 8a
(2)原式=-3xy2•5x 6y2
=-
;5x2 2
(3)原式=
•x(x-1) (x+1) (x+1)(x-1) (x-1)2
=x;
(4)原式=
•a(a+3b) -(a+b)(a-b) a-b a+3b
=-
.a a+b