问题
解答题
计算(1)
(2)
(3)
(4)(
|
答案
(1)原式=-
;6 ab
(2)原式=
=2x-(x+2) 2(x+2)(x-2)
;1 2x+4
(3)原式=
=9-(x+3)(x-3) x-3
;18-x2 x-3
(4)原式=
•(x+2)(x-2)-x(x-1) x(x-2)2
=x x-4
.1 (x-2)2
计算(1)
(2)
(3)
(4)(
|
(1)原式=-
;6 ab
(2)原式=
=2x-(x+2) 2(x+2)(x-2)
;1 2x+4
(3)原式=
=9-(x+3)(x-3) x-3
;18-x2 x-3
(4)原式=
•(x+2)(x-2)-x(x-1) x(x-2)2
=x x-4
.1 (x-2)2