问题 解答题
计算(1)
-9b
2a3
4a2
3b2

(2)
x
x2-4
-
1
2x-4

(3)
9
x-3
-x-3

(4)(
x+2
x2-2x
-
x-1
x2-4x+4
x-4
x
答案

(1)原式=-

6
ab

(2)原式=

2x-(x+2)
2(x+2)(x-2)
=
1
2x+4

(3)原式=

9-(x+3)(x-3)
x-3
=
18-x2
x-3

(4)原式=

(x+2)(x-2)-x(x-1)
x(x-2)2
x
x-4
=
1
(x-2)2

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