问题
解答题
计算. (1)
(2)
|
答案
(1)原式=
•x+2 -(x-2) -(x+2)(x-2) x(x+2)
=
;x+2 x
(2)原式=
•-(y-1) (y-2)2 (y+2)(y-2) (y+1)(y-1)
=-
.y+2 (y-2)(y+1)
计算. (1)
(2)
|
(1)原式=
•x+2 -(x-2) -(x+2)(x-2) x(x+2)
=
;x+2 x
(2)原式=
•-(y-1) (y-2)2 (y+2)(y-2) (y+1)(y-1)
=-
.y+2 (y-2)(y+1)