问题 解答题
计算:
(1)(
x
6y2
)2÷(-
x2
4y
)2

(2)(a-2b-1-3•(2ab2-2
(3)
m-m2
m2-1
÷
m
m-1
•(
m+1
m-1
)2

(4)1-
x-y
x+2y
÷
x2-y2
x2+4xy+4y2
答案

(1)原式=(

x
6y2
)2×(-
4y
x2
2=(
4xy
6x2y2
2=
4
9x2y2

(2)原式=(a2b)×

1
4
1
ab2
2=
a4
4b

(3)原式=

m-m2
m2-1
×
m-1
m
×(
m+1
m-1
2=
1+m
1-m

(4)原式=

3y
x+2y
x2+4xy+4y2
x2-y2
=-
3y
3(x+y)
=-
y
x+y

判断题
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