问题
解答题
计算: (1)
(2)(
|
答案
(1)原式=
+ab+b2 a2-b2
+a2-ab a2-b2
=2ab a2-b2
=(a+b)2 (a+b)(a-b)
;a+b a-b
(2)原式=
•2x x-3
-(x+3)(x-3) x
•x x+3 (x+3)(x-3) x
=2(x+3)-(x-3)=2x+6-x+3=x+9.
计算: (1)
(2)(
|
(1)原式=
+ab+b2 a2-b2
+a2-ab a2-b2
=2ab a2-b2
=(a+b)2 (a+b)(a-b)
;a+b a-b
(2)原式=
•2x x-3
-(x+3)(x-3) x
•x x+3 (x+3)(x-3) x
=2(x+3)-(x-3)=2x+6-x+3=x+9.