问题
解答题
计算: (1)
(2)
|
答案
(1)原式=
•x(x+1) x-1 x+1 x(x+1)2
=
;1 x-1
(2)原式=
•(x+2y)(x-2y) (x+y)2 x(x+y) x+2y
=
.x(x-2y) x+y
计算: (1)
(2)
|
(1)原式=
•x(x+1) x-1 x+1 x(x+1)2
=
;1 x-1
(2)原式=
•(x+2y)(x-2y) (x+y)2 x(x+y) x+2y
=
.x(x-2y) x+y