问题 解答题
计算:
(1)
x2+x
x-1
x+1
x3+2x2+x

(2)
x2-4y2
x2+2xy+y2
÷
x+2y
x2+xy
答案

(1)原式=

x(x+1)
x-1
x+1
x(x+1)2

=

1
x-1

(2)原式=

(x+2y)(x-2y)
(x+y)2
x(x+y)
x+2y

=

x(x-2y)
x+y

单项选择题
单项选择题