问题 解答题
计算:
(1)
ab3
2c3
÷
-5a2b2
4cd

(2)
x2-4y2
x2+2xy+y2
÷
x+2y
2x2+2xy
答案

(1)原式=

ab3
2c2
4cd
-5a2b2

=-

2bd
5ac2

(2)原式=

(x+2y)(x-2y)
(x+y)2
2x(x+y)
x+2y

=

2x(x-2y)
x+y

=

2x2-4xy
x+y

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