问题 解答题
通分;
(1)
4a
5b2c
5b
-2ac2

(2)
x-1
x2-2x+1
1
1-x
答案

(1)

4a
5b2c
=
8a2c
10ab2c2
5b
-2ac2
=-
25b3
10ab2c2

(2)

x-1
x2-2x+1
=
x-1
(x-1)2
=
1
x-1
1
1-x
=-
1
x-1

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