问题
解答题
通分; (1)
(2)
|
答案
(1)
=4a 5b2c
,8a2c 10ab2c2
=-5b -2ac2
;25b3 10ab2c2
(2)
=x-1 x2-2x+1
=x-1 (x-1)2
;1 x-1
=-1 1-x
.1 x-1
通分; (1)
(2)
|
(1)
=4a 5b2c
,8a2c 10ab2c2
=-5b -2ac2
;25b3 10ab2c2
(2)
=x-1 x2-2x+1
=x-1 (x-1)2
;1 x-1
=-1 1-x
.1 x-1