问题
填空题
已知：a2+4a+1=0，且
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答案
∵a2+4a+1=0，∴a2=-4a-1，
=a4+ma2+1 2a3+ma2+2a (-4a-1)2+ma2+1 2a(-4a-1)+ma2+2a
=(16+m)a2+8a+2 (m-8)a2
=(16+m)(-4a-1)+8a+2 (m-8)(-4a-1)
=
=3(-56-4m)a-14-m (-4m+32)a-m+8
即（-56-4m）a-14-m=（-12m+96）a-3m+24，
∴-56-4m=-12m+96，-14-m=-3m+24，
解得m=19．
故答案为19．